Y 3x 4
Parallel: y = 3x 4 (2, 7)?
y = mx + b
Where M is, in this case your number is 3, so for your lines to be parallel, your new equation must also have 3.
Now enter: 7 = 3 (2) + b = 6 + b
So B is equal to one.
So your answer is y = 3x + 1
Hey, if the lines are parallel, the error is like the lines.
That is, y = 3x 4 here m = 3 [think of the common form y = mx + c]
So meter = 3
And the points are (2, 7)
So the equation is in terms of a point
(y7) = 3 (x2)
y = 3x + 1
For the linear equation, the intersection type (to the right of the moment) is y = mx + b. Dance Le Cass O س Vos Obtniz + 1 e Tout en Sutilisent pig zone du sign equivalent, Alvars IC les information vra es are: M, C East l'Mumble è M de la Ligni, ST Lee Confidence of XB East Lanterction Y, that's it . The y-axis situation where the lines intersect with the time of your query, both equations are already abnormal intersection type y = (4/3) x + (7/3) for m = 4/3 Are Multiply whatever you want and return with four / 3 so that 4/3 and = (4/3) x9 / 4 have one m = 4/3 which is 4/3 for both hits. Because your positions are the same, the tracks are parallel.