Vector A Is 3.0 Units In Length And Points Along

Vector A Is 3.0 Units In Length And Points Along

Vector A is 3.0 units long and is represented by an x ​​= positive axis. Hey B 4.0 unit tall and displays? 3

Vector A is 3.0 units long and points with a positive X axis. Vector B is 4.0 units long and points 150 degrees to the positive x-axis. What is the amplitude of the result if vectors A and B are combined?

The x component of A is 3.0 and its y component is 0.

B = B * cos (theta) = 4.0 * cos (150) = the x component of 3.46 and its y component = B * sin (theta) = 4.0 * sin (150) = 2

Now if similar components are added then x = 3.0 3.46 = 0.46 y is component 2

Result intensity = square (x 2 + y 2) = square (46) 2 + 2 2) = 2.05

Vector A Is 3.0 Units In Length And Points Along

Vector A Is 3.0 Units In Length And Points Along

All you have to do is get vector b / vector a (three / 6 or 0.5 arctan). This gives you the relative degrees of x-axis ... Just understand that part (a) you have inconsistent values ​​and part b) you have big values.

Vector A Is 3.0 Units In Length And Points Along