V 4 3πr3

V 4 3πr3

Solve for V = 4 / 3Ã € r3 and r? 3

update

The answer is a cubic root of 2 6 2V over € 2. I just wanted to know if that was the answer.

V = 4 / 3Ã Âr 3

r 3 = 3/4 * V /

r = Quc root [3/4 * V / €].

PS: I don't think your answer is equal to 6V over 6 ft 2V 2 ft and is not correct. It may be fair if you have additional information about V Terms or something similar. I do not know. We're sorry!

V = 4/3 TT r 3, take TT for pi because I can't write it

Divide both sides by 4/3: Anything that can be divided by the form a / b, where b is not 0, is the same thing that is multiplied by b / a, where a is not 0. So divide V by. For 4/3 = 3 / 4V ... OK? And a similar distribution of equations on the right removes 4/3.

3/4 V = TT r 3 ... Now divide both sides by pi and you have.

3/4 * 1 / ST * V = 3V / 4TT = r 3 .... then connect the cubes on both sides. The correct one would be r. NS

r = (3V / 4TT) 1/3 .... Remember that when a number is added to any number 1 / a (where a is different from 0) then the root of this number is equal to happens. So, going from 3V / 4TT to 1/3, we have a cubic root of 3V / 4TT. So your answer is:

r = (3V / 4TT) 1/3

Volume of the sphere = 4/3 * pi * radius 3

To solve r, you need to know the volume.

To find the volume, you need to know what r is.

V 4 3πr3