The Empirical Formula For Trichloroisocyanuric Acid

The Empirical Formula For Trichloroisocyanuric Acid

About the experimental formula? 3

The experimental formula of trichloroisocyanuric acid, the active ingredient in many bleaches used, is OCNCL. The mold of this compound is 23.41 g / mol. What is the molecular formula of trichloroisocyanuric acid?

1) OCNCL

2) O3C3N3Cl3

3) O2C4N4Cl4

4) O5C5N5Cl5

5) O2C2N2Cl2

OCNCl = 16 + 12.011 + 14.006 + 35.453 = 77.47

You probably mean M مولller M232.41. as well as

3x77.47 = 232.41

2) O3C3N3Cl3 is the experimental formula.

Trichlorine should be the only tip you need :)

Well, I'm going to take Cl3 (CN) 3O3 (2) based on the fact that it has 3 chlorine groups and 3 cyanide groups and you are right ... but we will rely on the information provided. ..

Now we know that the experimental formula is OCNCl. it is

Which means that for every atom of carbon, nitrogen and chlorine there is 1 atom of oxygen ...

To find the molar m, you must first calculate the molar m of the OCNCl molecule ...

Oxygen contains atoms of m ... 15.9994 (3) € g · mole Â'1

Carbon has atoms of m ... 12.0107 (8) € g · mole ˆÂ'1

Nitrogen atoms m ... 14.007 (2) € g · mole Â'1

The atom of chlorine is meter ... 35,453 (2) g · mole Â'1

This shows that m OCNCl is 77.4701 gmol  Â'1

So I'm going to take the molar data m ... 23.41 and distribute it to you, which is 0.302.

This would contain 0.302 oxygen atoms, 0.302 nitrogen atoms, 0.302 carbon atoms and 0.302 chlorine atoms in the molecule ... which is probably a branch of nuclear physics, so this is wrong ...

Assuming there are 3 atoms of oxygen, nitrogen, carbon and chlorine, then you can find the real molecule of the molecule.

3 x 77.4701gmol ˆÂÂ'1 = 232.4103 g / mol

Which actually indicates that the molar of this compound is 232.41 grams / mol, which is probably what is written on the sheet ...

The Empirical Formula For Trichloroisocyanuric Acid