Tan Pi 6

Tan Pi 6

Can anyone solve: tan ((pi / 6) + (3pi / 4))?

Tan (Ã Â € / 6) = 1 / -3.

tan (3Ã Â € / 4) = tan (Ã Â € / 4) = 1 ======> tan (A) = chocolate (€ € € A)

Brown ((leg / 6) + (3pi / 4))

= [tan (Ã € / 6) + tan (3Ã € / 4)] / [1 (tan ((€ / 6)) (tan (3Ã € / 4))] => tan (A + B) = [ Tan (A) + Tan (B)] / [1 Ton (A) Tan (B)

= [1 / -3 1] / [1 (1 / -3) (1)]

= [1 / -3 1] / [1 + 1 / -3]

= [1 / -3 3]

= [1/3 2 / -3 +1] / [1/31]

= [4/3 2/3 (Ã -3)] / [2/3]

= 3 2.

For example, answer your question.

Tan Pi 6