**S Has Degree 4 And Zeros 2i And 3i**

(x 2i) (x + 2i) (x 3i) (x + 3i) = 0

(x 2 + 4) (x 2 + 9) = 0

x 4 + 13x 2 + 36 = 0

Â

Since the coefficients are rational, if a complex number is a + root, its conjugate number will also be aÃ Â '.

Zs = 2i, 3i, Â'2i, ÂˆÂ'3i

x = ± 2i

xÃ‚Â² = 4iÃ‚Â² = Â'4

x² + 4 = 0

x = ± 3i

xÃ'Â² = 9iÃ'Â² = Â'9

x² + 9 = 0

f (x) = (x² + 4) (x² + 9)

f (x) = xÃ´ + 13xÃ‚Â² + 36

2i and 3i should also be rooted, so:

a (x + 3i) (x3i) (x + 2i) (x2i) = 0 is one such equation.

Shows progress and arrival conditions:

a (x 4 + 13x 2 + 36) = 0

Cost a = 1 answers:

x 4 + 13x 2 + 36 is a plural name.

(x 2 + 4) (x 2 + 9) has zs 2i, 2i, 3i, 3i and its degree is 4