# Range Of A Parabola

## Range Of A Parabola

### How do you find Domain and Beach without a card in Parla? 3

J'ai revisé pour mon exam mathématiques de 10e année, plus j'ai été ■■■■■■■é jab m'a donné par 5/4 (x + 2)

Each speech contains a domain x = all real numbers.

The interaction status is determined by the y value of the host node and whether the interaction is open or not.

Perfect shape:

f (x) = a (a h) with the vertical of 2 + k (h, k)

f (x) = 5/4 (x + 2) 2 1 has a vertical (2.1)

As 5/4 is a positive number, the package opens in U-shape and when the package is opened it has a small dot which is on top of the package. Minimum point (2.1). Since we are looking for an interval, we want to see the value of t y, or at least its point, which is 1. The graph cannot be less than 1, so the interval is y> / 1.

To find the y-intercept, change x to 0 and solve.

To find the X intercept, change y to 0 and solve.

Help, for example

## Range Of A Parabola

5/4 (x + 2) 2 1

It helps if your equation is clear. Is 5 divided by 4 or 4 (x + 2) divided by 2? It made a big difference for us.

If the equation is 1.25 * (x + 2) 2 1, then the domain is made up of all the real values ​​of x. In fact, the radius along the symmetry axis parallel to the y axis is a continuous function.

This equals the minimum value because the coefficient x is positive. You get the node, then you know the value of y, which is equal to the value of y on that node. Therefore, the range contains all real values> node y.

The radius of the shape (yk) = 4p (xh) 2 (meaning it has the term x-square, not the term y) has a peak (h, k) and has one of two different shapes: open Or open When p is negative, it opens downwards. When p is positive (as in your example), it opens.

So the area depends on where the point and curve are. If the tongue opens downwards, the range is y = k.

The domain will be a set of all real numbers because x is an independent variable. Regardless of whether or not Parla is facing.

## Range Of A Parabola

Domains are just all the x values ​​on which the function is defined. In this case, you can enter any x value and get a single y value so that all real numbers are included in the domain.

The range includes all the y values ​​for which the function is defined. You can find it through us. We see that the smallest value of y can be 1 if x = 2. So a range greater than or equal to 1 contains all real numbers.

The domain consists entirely of real numbers. There are no disturbing x values.

The beach is easy to find after the peak. If the n value of the v node is (1 in your example), then the range is y> = v or y = 1

Well, for the first part you said that y / x 2 = 1 here you are going to solve if y is divided by x squared is equal to one, so you are going to use pairs and x The answer is no. Coordinate containing. The same goes for the second part. Basically, you will not make a graph of x / y 2 = (number) that solves one point.

w To explore the beach