**Prime Factorization Of 100**

### What is the basic element of 100? College?

100! This is a very large number ... not 100 ... this is 100 x 99 x 98 x 97 x 96 x 95 ..... x 1.

2 97 + 3 47 + 5 24 + 7 16 + 11 9 + 13 7 + 17 5 + 19 5 + 23 4 + 29 3 + 31 3 + 37 2 + 41 2 + 43 2 + 47 2 + 53 + 59 + 61 + 67 + 71 + 73 + 79 + 83 + 89 + 97 + 97

The algorithm is like this

With only 2

100 / (2 1) = 50.

100 / (2 2) = 25.

100 / (2 3) = 12 (Actually this is a fraction, but when we talk about prime factoring we only look at the whole number. Keep the rest of the problem in mind)

100 / (2 4) = 6.

100 / (2 5) = 3.

100 / (2 6) = 1.

100 / (2 7) = 0, for the number, so let's stop here.

Now add all the tse numbers to get 97.

There, 2 split 100! 97 times

Repeat for the remaining prime numbers

The basic element of 100.

maybe not. I will support my claim, keeping in mind that there is no clear way to change the basic numbers. If we can't find the primes of a number, would you suggest that we look for the factors of one number in another number? Add: I am familiar with the primate test mentioned by Icarus, such as using Wilson's theory (seriously, this is one of the two that I know is 100% guaranteed), however they are ineffective and unlikely to be seen. Are much more useful. (not me) . Not sure if this is the correct word (test). Test 100 is very difficult to apply. Another addition: The twin cousins are thought to be a great example of why we don't know this. Increase in other quantities: n is prime and n + 2 is prime. We don't know if there are endless cases. If we know that n is done from n + 1 and n + 1 to n + 2, we know that n is done from n + 2. Add: OK, man ... I'm giving up. Add: Chaser, no problem with logic. If j and k are prime of each other then m and n are prime of each other. You got lost in the previous answer.

Voice conflict, the use of this algorithm is very useful. Thank you very much. But I think the factors increase, they don't increase ...