**How Many Different Sequences Of Eight Bases Can You Make**

10 points for DNA? 3

small:

There are 4 basic bases for each position, A, G, C, T.

How many different layouts can you create if you want to use 2 basic layouts instead of 8?

16 different configurations are possible:

AAAAGAACAT

GAGGGCGT

AC CG CC CT

TATG TTCT

Count them, the answer is 16.

Now that we have neither the time nor the patience to look for the 8 basic sequences in the same way, what formula can we use to calculate the answer?

We only need 2 sequences, each of which can be one of 4 different bases. This means that there are 4 possibilities for each of the 2. That is 4 to 4x4 = 16.

Now we need a sequence of 8, each of which can be one of 4 different bases. This means that there are 4 possibilities for each of the 8. That is, four to eight.

4 x 4 x 4 x 4 x 4 x 4 x 4 x 4 = 65,536 Possible layouts

Do you remember if it was 4-8 or 8-4? There is a big difference.

Always with 4, because it's a constant, there are 4 bases, A, G, C and T.

The answer is 4 8 = 65,536 separate strings.

There are four possible bases that can be in any position on the wire. So, for wires with only one position, you have 4 options. Add another position and you get (4) (4) = 4 2 = 16 chances. Keep multiplying by the number of your positions and Vavila!

Only 1

Only AT and GC

There is no other way!