1 answer. Al E. Sulfuric acid is the conjugate acid of hydrogen sulfide, in which it is dissociated in solution.
In summary, it can be represented by the following chemical reaction: acid + base ⇌ conjugated base + conjugated acid. Table of acids and their conjugated bases.
|Sulfuric acid H2S||HS (hydrogen sulfide ion)|
A strong acid is one that is fully ionized in an aqueous solution. Hydrochloric acid (HCl) completely ionizes in water to form hydrogen ions and chloride ions. Since HCl is a strong acid, its conjugate base (Cl-) is extremely weak.
The 7 common strong acids are: HCl, HBr, HI, HNO3, HClO3, HClO4 and H2SO4 (only the first proton). They just don’t ionize completely, unlike a strong acid or base. This means that for a 0.1 M HCl solution versus 0.1 M HF, the HCl solution contains more H + and is more acidic.
CH3CH2OH can be a Brönsted-Lowry acid. C) CH3CH2OH can be a Brönsted-Lowry acid, CH3CH2NH2 can be a Brönsted-Lowry base and CH3CH2OH can be a Lewis base.
An acid dissociation constant Ka (also called acidity constant) is a quantitative measure of the strength of an acid in solution. It is the equilibrium constant of a chemical reaction. known as dissociation associated with acid-base reactions.
A buffer solution is a solution that can resist changes in pH when small amounts of acid or alkali are added. An acidic buffer solution is simply a solution with a pH below 7. Acidic buffer solutions generally consist of a weak acid and one of its salts is often a sodium salt.
Answer and explanation:
CH3COOH is a weak acid and partially dissociates in solution (as indicated by a reversible arrow) to form H + and CH3COO ions. Since this is a reversible process, CH3COO can absorb H + to form CH3COOH in turn. Hence, the nature of CH3COO is fundamental and we call CH3COO the conjugate base of CH3COOH.
The conjugated acid for S2 - S 2 - is HS - HS -. Add a proton to determine the conjugate acid. A proton is an H + H +, so to determine the conjugate acid, add an H and a +1 to the base charge.
In CH3OH there are lone pairs on the O atom. CH3OH acts as the base and CH3OH2 + is the conjugated acid. The addition of H + to the conjugate base gives the conjugate acid.
In the above reaction, methylamine takes a proton from water and is therefore a Brönsted base. The reverse is true for the reverse reaction, as CH3NH3 + releases a proton to the hydroxide and classifies it as Brönsted’s acid. Therefore, CH3NH3 + is the conjugate of methylamine.
The conjugate base is the chloride anion (Cl-), which has the potential to act as a proton acceptor. However, no H-OHorCl– has electrostatic properties strong enough to interact in a proton transfer process to transfer hydrogen back to the hydroxide ion.
Answer and explanation:
NaOH is a base because it breaks down into Na + and OH ions when it dissolves in water. It is OH (hydroxyl ions) that converts NaOH to a base. In the conventional term, a base is defined as a compound that reacts with an acid to form salt and water, as shown by the following equation.