Applied physics

For the combinational circuit below:
R1= 7.2K
R2= 2.8K
R3= 5.6K
R4= 3.9K
R5= 1K
R6= 4.7K
R7= 2.3K
R8= 5.8K

  1. Measure current and voltage across each resistor in the circuit
  2. Calculate Rt, Vt, It and show all steps of circuit reduction and calculation

RESISTOR VOLTAGE CURRENT POWER

R1= 7.2k V1= 6.74V I1= 0.936mA P1= 6.308×10-3 W

R2= 2.8k V2=2.622V I2=0.936mA P2=2.454×10-3 W

R3= 5.6k V3=2.638V I3= 0.471mA P3=1.242×10-3 W

R4= 3.9k V4=1.815V I4=0.465mA P4=0.843×10-3 W

R5= 1k V5=0.323V I5=0.323mA P5=0.104×10-3 W

R6= 4.7k V6=0.499V I6=0.106mA P6=0.052×10-3 W

R7= 2.3k V7=0.499V I7=0.217mA P7= 0.108×10-3 W

R8= 5.8k V8= 0.823V I8=0.142mA P8=0.116×10-3 W

CALCULATIONS:

VA = V6 = V7

VA = 0.499 = 0.499

VA =0.499V

VB = V5 + VA

VB = 0.323 + 0.499

VB = 0.822V

VC = VB = V8

VC = 0.822 = 0.823

VC = 0.823V

VD = VC + V4

VD = 0.823 + 1.815

VD = 2.638V

VE = VD = V3

VE = 2.638 = 2.63

VE = 2.63V

VT = V1 + V2 + VE

VT = 6.74 + 2.622 + 2.638

VT = 12V